Optimal. Leaf size=242 \[ -\frac{d^{3/4} \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right ),\frac{1}{2}\right )}{231 c^{13/4} e^{13/2} \sqrt{c+d x^2}}-\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}-\frac{2 \sqrt{c+d x^2} \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right )}{231 c^3 e^5 (e x)^{3/2}}-\frac{2 a \sqrt{c+d x^2} (22 b c-9 a d)}{77 c^2 e^3 (e x)^{7/2}} \]
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Rubi [A] time = 0.2216, antiderivative size = 242, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179, Rules used = {462, 453, 325, 329, 220} \[ -\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}-\frac{d^{3/4} \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{231 c^{13/4} e^{13/2} \sqrt{c+d x^2}}-\frac{2 \sqrt{c+d x^2} \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right )}{231 c^3 e^5 (e x)^{3/2}}-\frac{2 a \sqrt{c+d x^2} (22 b c-9 a d)}{77 c^2 e^3 (e x)^{7/2}} \]
Antiderivative was successfully verified.
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Rule 462
Rule 453
Rule 325
Rule 329
Rule 220
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt{c+d x^2}} \, dx &=-\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}+\frac{2 \int \frac{\frac{1}{2} a (22 b c-9 a d)+\frac{11}{2} b^2 c x^2}{(e x)^{9/2} \sqrt{c+d x^2}} \, dx}{11 c e^2}\\ &=-\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}-\frac{2 a (22 b c-9 a d) \sqrt{c+d x^2}}{77 c^2 e^3 (e x)^{7/2}}+\frac{\left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \int \frac{1}{(e x)^{5/2} \sqrt{c+d x^2}} \, dx}{77 c^2 e^4}\\ &=-\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}-\frac{2 a (22 b c-9 a d) \sqrt{c+d x^2}}{77 c^2 e^3 (e x)^{7/2}}-\frac{2 \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \sqrt{c+d x^2}}{231 c^3 e^5 (e x)^{3/2}}-\frac{\left (d \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right )\right ) \int \frac{1}{\sqrt{e x} \sqrt{c+d x^2}} \, dx}{231 c^3 e^6}\\ &=-\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}-\frac{2 a (22 b c-9 a d) \sqrt{c+d x^2}}{77 c^2 e^3 (e x)^{7/2}}-\frac{2 \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \sqrt{c+d x^2}}{231 c^3 e^5 (e x)^{3/2}}-\frac{\left (2 d \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c+\frac{d x^4}{e^2}}} \, dx,x,\sqrt{e x}\right )}{231 c^3 e^7}\\ &=-\frac{2 a^2 \sqrt{c+d x^2}}{11 c e (e x)^{11/2}}-\frac{2 a (22 b c-9 a d) \sqrt{c+d x^2}}{77 c^2 e^3 (e x)^{7/2}}-\frac{2 \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \sqrt{c+d x^2}}{231 c^3 e^5 (e x)^{3/2}}-\frac{d^{3/4} \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{231 c^{13/4} e^{13/2} \sqrt{c+d x^2}}\\ \end{align*}
Mathematica [C] time = 0.23611, size = 196, normalized size = 0.81 \[ \frac{x^{13/2} \left (-\frac{2 \left (c+d x^2\right ) \left (3 a^2 \left (7 c^2-9 c d x^2+15 d^2 x^4\right )+22 a b c x^2 \left (3 c-5 d x^2\right )+77 b^2 c^2 x^4\right )}{c^3 x^{11/2}}-\frac{2 i d x \sqrt{\frac{c}{d x^2}+1} \left (45 a^2 d^2-110 a b c d+77 b^2 c^2\right ) \text{EllipticF}\left (i \sinh ^{-1}\left (\frac{\sqrt{\frac{i \sqrt{c}}{\sqrt{d}}}}{\sqrt{x}}\right ),-1\right )}{c^3 \sqrt{\frac{i \sqrt{c}}{\sqrt{d}}}}\right )}{231 (e x)^{13/2} \sqrt{c+d x^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.031, size = 411, normalized size = 1.7 \begin{align*} -{\frac{1}{231\,{x}^{5}{c}^{3}{e}^{6}} \left ( 45\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticF} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ) \sqrt{-cd}{x}^{5}{a}^{2}{d}^{2}-110\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticF} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ) \sqrt{-cd}{x}^{5}abcd+77\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticF} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ) \sqrt{-cd}{x}^{5}{b}^{2}{c}^{2}+90\,{x}^{6}{a}^{2}{d}^{3}-220\,{x}^{6}abc{d}^{2}+154\,{x}^{6}{b}^{2}{c}^{2}d+36\,{x}^{4}{a}^{2}c{d}^{2}-88\,{x}^{4}ab{c}^{2}d+154\,{x}^{4}{b}^{2}{c}^{3}-12\,{x}^{2}{a}^{2}{c}^{2}d+132\,{x}^{2}ab{c}^{3}+42\,{a}^{2}{c}^{3} \right ){\frac{1}{\sqrt{d{x}^{2}+c}}}{\frac{1}{\sqrt{ex}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{2} + a\right )}^{2}}{\sqrt{d x^{2} + c} \left (e x\right )^{\frac{13}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b^{2} x^{4} + 2 \, a b x^{2} + a^{2}\right )} \sqrt{d x^{2} + c} \sqrt{e x}}{d e^{7} x^{9} + c e^{7} x^{7}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{2} + a\right )}^{2}}{\sqrt{d x^{2} + c} \left (e x\right )^{\frac{13}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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